Question

Simplify using a table (6q+7)(2q+3)

Answer 1

(6q+7)(2q+3)
12q^2 + 18q + 14q + 21
12q^2 + 32q + 21

Answer 2

`\:\:\left(6q+7\right)\left(2q+3\right)=12q^2+32q+21`

Table is shown below

Explanation:

Given expression
`\:\:\left(6q+7\right)\left(2q+3\right)`

We have to find the product of given expression using table.

Consider the given expression
`\:\:\left(6q+7\right)\left(2q+3\right)`

We have to find the product of given expression
`\:\:\left(6q+7\right)\left(2q+3\right)`

Apply FOIL METHOD,

Multiply Each term in first bracket with each term in second bracket,

`\left(a+b\right)\left(c+d\right)=ac+ad+bc+bd`

We have,

`=6q\cdot \:2q+6q\cdot \:3+7\cdot \:2q+7\cdot \:3`

Simplify, we have,

`=6\cdot \:2qq+6\cdot \:3q+7\cdot \:2q+7\cdot \:3`

Simplify, we have,

`=12q^2+32q+21`