Question

Can u please help me before it kicks me out of the tutoring.Solve the linear system of equations.

Answer 1

Solving by elimination method.

We have the following system of equations:

`\begin{gathered} 5x-y=2 \\ -9x+y=-10 \end{gathered}`

If we add both equations, we have

`5x-9x=2-10`

because -y+y=0. That is, we have eliminated y.

Now, by combining similar terms, we obtain

`-4x=-8`

If we move -4 to the right hand side, we have

`\begin{gathered} x=(-8)/(-4) \\ x=2 \end{gathered}`

Now, we can substitute this value into the first equation. It yields

`\begin{gathered} 5(2)-y=2 \\ 10-y=2 \end{gathered}`

If we move +10 to the right hand side as -10, we have

`\begin{gathered} -y=2-10 \\ -y=-8 \\ y=8 \end{gathered}`

Therefore, the answer is x=2 and y=8.