Question

A gas is cooled from 365 K to 285 K while its volume changes from 12.8 L to 9.9 L. The initial pressure of the gas is 1.9 atm. The final pressure of the gas, rounded to the nearest tenth, is atm.

Answer 1

`\mathsf{(P_(1)\cdot V_(1))/(T_(1))=(P_(2)\cdot V_(2))/(T_(2))}`



`\mathsf{(1,9\cdot 12,8)/(365)=(P_(2)\cdot 9,9)/(285)}`



`\mathsf{(24,32)/(365) = (9,9\cdot P_(2))/(285)}`



`\mathsf{9,9\cdot365\cdotP_(2)=24,32\cdot285}`



`\mathsf{3613,5\cdot P_(2)=6931,2}`



`\mathsf{P_(2)=(6931,2)/(3613,5)}`



`\mathsf{\boxed{P_(2)=1,92~atm}}`


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