Question

John is playing a game of darts. The probability that he throws a dart into the center of the dart board (the Bull’s eye) is . The probability that he throws the dart into the 10-point ring is . What is the probability that he either hits a Bull’s eye or scores 10 points?

1/3
2/3
3/5
2/5
1/4

Answer 1

2/5

Explanation:

Plato said it was right

Answer 2

`(2)/(5)` is the required probability.

Explanation:

The probability P(A or B) when A and B are mutually exclusive events is P(A) + P(B)

Here A is the event hitting a Bull's eye

and B is the event throwing dart into 10 point ring.

The probability that he throws a dart into the center of the dart board (the Bull’s eye) =
`(1)/(10)`.

The probability that he throws the dart into the 10-point ring =
`(3)/(10)`

Required probability =
`(1)/(10)`+
`(3)/(10)` =
`(4)/(10)` =
`(2)/(5)`