Question

The curve y = |x|/(sqrt(5- x^2)) is called a bullet-nose curve. Find an equation of the tangent line to this curve at the point (2, 2)

Answer 1

absolute value
at x=2, the absolute value thing is positive
do this one

`y=x √(5-x^2)`
the derivitive is

`(dy)/(dx)=√(5-x^2)- (x^2)/( √(5-x^2) )`
so the slope at x=2 is

`(dy)/(dx)=√(5-2^2)- (2^2)/( √(5-2^2) )`=-3

a point is (2,2)
point slope form
y-y1=m(x-x1)
y-2=-3(x-2)
or
y=-3x+8
das is de equation