The molarity (M) of a solution is the number of moles of solute dissolved in one liter of solution. To calculate the molarity of a solution, divide the moles of solute by the volume of the solution expressed in liters:
We have to convert 152.9 mL to liters (L). Remember that 1 liter equals 1000 mL:
And we have to solve for 'moles' from the formula of molarity:
And finally, we replace the given molarity (0.452 M) and the volume of solution which is 0.1529 L:
Now, that we have the number of moles of NaNO3, we have to calculate its mass in grams. We have to use the molar mass of NaNO3 which is 85 g/mol (you can calculate the molar mass using the periodic table). The conversion from 0.0691 moles of NaNO3 to grams would be:
The answer is that we have 5.87 grams of NaNO3 in 152.9 mL of 0.452 M of NaNO3.