Answer:
Step-by-step explanation:A. enter pool is when h(t)=0
B. max height is the vetex
C. that is the t value of the vertex
A.
0=-16t²+24t+40
using math
t=-1 or 5/2
can't be negative time
t=5/2
after 2.5 seconds
B. find vertex
get into form
y=a(x-h)^2+k
complete the square
h(t)=-16t²+24t+40
h(t)=(-16t²+24t)+40
h(t)=-16(t²-1.5t)+40
h(t)=-16(t²-1.5t+0.5625-0.5625)+40
h(t)=-16((t-0.75)²-0.5625)+40
h(t)=-16(t-0.75)²+9+40
h(t)=-16(t-0.75)²+49
vertex is at t=0.75 and h(0.75)=49
A. after 2.5 seconds
B. 49ft
C. 0.75 seconds