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Gregor Mendel studied the inheritance of traits in pea plants. One trait he examined was the height of the plant. Pea plants with the dominant 'T' allele grew tall, and pea plants with the recessive allele 't' were short. According to Mendel's principles of heredity, if a homozygous tall pea plant was crossed with a homozygous short pea plant, approximately how many of their offspring would have the short phenotype?

User Robot
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2 Answers

4 votes
0% since none of the offspring would be homozygous recessive
User Martin Lyne
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6 votes

Answer:

0

Step-by-step explanation:

None of the offspring will appear tall.

Homozygous pea plant genotype = TT

Homozygous short plant genotype = tt

Crossing the the homozygous tall plant (TT) with homozygoys short plant (tt):

TT x tt = Tt, Tt, Tt, and Tt

Since the T allele is dominant over the t allele, it means all the offspring will appear tall.

Hence, none of the offspring will appear short phenotypically.

The answer is 0.

User Scott Johnson
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