Question

the sum of three numbers is 45. the second of the three numbers is three more than twice the first number, x. the third number is two more than the first number, x. which equation can be used to solve for the first number, x?

Answer 1

The numbers are 20,15 and 10

Answer 2

x+ (2x+3) +(x+2)=45

Explanation:

First number is x

So using this ,second number which is three more than twice of the first can be written as 2x+3

Now , The third number is two more than the first so it is x+2

Sum of the three numbers can be written as

x+ (2x+3) +(x+2)

In the question it is given that the sum is 45 so we can equate the equation in x to the given sum to solve it for x .

Hence

x+ (2x+3) +(x+2) =45