Given that a line passes through the point (3,−7) and has a slope of −43. − 4 3 . Hence, the equation of the given line is 4x+3y+9=0.
Answer:
y = -4x/3 -3
Explanation:
y - y1 = m( x - x1 )
y - -7 = -4/3 ( x - 3 )
y + 7 = -4x/3 + 4
y = -4x/3 -3 is the equation of the line
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