Question

Find the number of real number solutions for the equation.

X^2-10x+25=0

A: 2
B: Cannot be determined
C: 0
D: 1

Answer 1

Hello here is a solution :
x²-10x+25 = 0
x² -2(x)(5)+5² =0
puy identity : a²-2ab+b² = (a-b)²
(x-5)² = 0
x-5 = 0
the solution is : 5

Answer 2

Determinant = b² - 4ac = (-10)² + 4*1*25 = 100 - 100 = 0

So it has 1 solution.
Answer is D