Find the standard score (z) such that the area below the mean and below z is about 16% of the area under the normal curve.

asked Dec 22, 2018 94.6k views

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4 votes

A probability of 0.16 corresponds to a z-score of approximately
$z\approx-0.994$ , i.e.

$\mathbb P(Z<-0.994)=0.16$

Rick Liao answered Dec 26, 2018

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