Answer:
200 in³
Step-by-step explanation:
The lengths of the sides of the constructed tetrahedron are twice the length of the side of the small tetrahedron of 50 in³. It means that the scale factor for the solid is 2. So, the complete volume of the constructed tetrahedron is equal to
Vn = 2³(50 in³)
Vn = 8(50 in³)
Vn = 400 in³
However, we only use 4 small tetrahedrons, so the volume of these four solids is
4(50 in³) = 200 in³
Then, the volume of the gap is the difference between the volume of the constructed tetrahedron and the volume of the 4 small tetrahedrons
400 in³ - 200 in³ = 200 in³
So, the answer is 200 in³