Answer:
Suppose every object in the domain has only one image in the codomain, then the mapping is a function. Otherwise, it is not a functions
Looking at the given mapping:
-2 is mapped to both 1 and 3
0 is mapped to -3
1 is mapped to 4
3 is mapped to 1
Because -2 has more than one image, it disqualifies the mapping from being a function.