Register
The width of a rectangle is 7 less than twice the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the rectangle?
119k views
3 votes
The width of a rectangle is 7 less than twice the length. If the perimeter of the rectangle is 43.6 inches, what is the area of the rectangle?

User Peterhil
by
5.4k points

1 Answer

5 votes
I hope this helps you


w = 2l-7


2 (2l-7+l)=43,6


3l-7=21,8


3l=28,8l=9,6


w=2.9,6-7=12,2



Area=9,6.12,2=117,12
User Vamshi Suram
by
6.2k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

6.5m questions

8.7m answers

Other Questions

What is the least common denominator of the four fractions 20 7/10 20 3/4 18 9/10 20 18/25
What is 0.12 expressed as a fraction in simplest form
Solve using square root or factoring method plz help!!!!.....must click on pic to see the whole problem
What is the initial value and what does it represent? $4, the cost per item $4, the cost of the catalog $6, the cost per item $6, the cost of the catalog?
What is distributive property ?
Link Copied!