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Convert the rectangular equation to a polar equation, 9x+y=10

User Fida
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\bf 9x+y=10\qquad \begin{cases} x=rcos(\theta)\\ y=rsin(\theta) \end{cases}\quad thus\quad 9rcos(\theta)+rsin(\theta)=10 \\\\\\ \textit{polar equations are in }\theta\textit{ terms, thus} \\\\\\ r[9cos(\theta)+sin(\theta)]=10\implies r=\cfrac{10}{9cos(\theta)+sin(\theta)}
User Fasti
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