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Last questions; I NEED HELP!

Last questions; I NEED HELP!-example-1
Last questions; I NEED HELP!-example-1
Last questions; I NEED HELP!-example-2
User Boob
by
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1 Answer

2 votes
given that cos Ф = 5/6 I know that one side is 5 and the hypotenuse is 6 so the other side is:
a^2 = c^2 - b^2
a^2 = 6^2 - 5^2
a^2 = 36 - 25 = 11
a =
√(11)

Now I know that the sin is
( √(11) )/(6) since sin is defined as opposite/hypotenuse

the second one uses a form of C = pi * d we are going to add the sector part to it.
C = 6 and the central angle is 4 degrees we can set up like this:

6 = (4)/(360)* \pi *d

(6 * 360)/(4 * \pi ) = d
d = 171.974
r = 171.94/2 =85.987
User Joe Mahoney
by
8.7k points

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