Question

How many liters of 1.75 M solution could be made using 35 grams of NaCl?

Answer 1

Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:

`M = (m)/(MM*V)`

Solving:

`M = (m)/(MM*V)`

`1.75 = (35)/(58.44*V)`

`1.75*58.44V = 35`

`102.27V = 35`

`V = (35)/(102.27)`

`\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark`