Question

If f(x)=4x^2-3 and g(x)=x+1,find (f-g)(x)

A.4x^2-x-2
B.4x^3-3
C.x-4x^2-2
D.4x^2-x-4

Answer 1

Hello here is a solution :

(f-g)(x) =f(x) - g(x)
= (4x²-3)-(x+1)
= 4x² -x -4 ( answer :D)

Answer 2

Option D is correct

The value of
`(f-g)(x)` is,
`4x^2-x-4`

Explanation:

Given the function:

`f(x) = 4x^2-3`

`g(x) = x+1`

We have to find
`(f-g)(x)`

`(f-g)(x) = f(x)-g(x)`

Substitute the given functions we have;

`(f-g)(x) = 4x^2-3-x-1`

⇒
`(f-g)(x)=4x^2-x-4`

Therefore, the value of
`(f-g)(x)` is,
`4x^2-x-4`