Question

Determine the volume occupied by 0.352 mole of a gas at 25⁰C if the pressure is 81.8 kPa.

Answer 1

Data:
p (pressure) = 81.8 kPa = 81.8*10³ Pa ≈ 8.07 atm
v (volume) = ? (in L)
n (number of mols) = 0.352 mol
R (Gas constant) = 0.082 (atm*L/mol*K)
T (temperature) = 25ºC converting to Kelvin, we have:
TK = TC + 273 → TK = 25 + 273 → TK = 298

Formula:

`p*V =n*R*T`

Solving:

`p*V =n*R*T`

`8.07*V = 0.352*0.082*298`

`8.07V \approx 8.60`

`V \approx (8.60)/(8.07)`

`\boxed{\boxed{V \approx 1.06\:L}}`