Question

A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green. The probability of the arrow landing on a section colored red is 25%. The probability of the arrow landing on a section colored blue is 10%. What is the probability of the arrow landing on a section colored green?

Answer 1

I believe it is 65% because you add 25% and 10% together then subtract from 100, because percent means per 100. So, sorry if I am wrong.  

Answer 2

The probability of the arrow landing on a section colored green is 65%.

Explanation:

Given : A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green.

The probability of the arrow landing on a section colored red is 25%.

The probability of the arrow landing on a section colored blue is 10%.

To find : The probability of the arrow landing on a section colored green

Solution :

→ The probability of the arrow landing on a section colored red is 25%.

i.e,
`P(R)=25\%=(25)/(100)=0.25`

→ The probability of the arrow landing on a section colored blue is 10%.

i.e,
`P(B)=10\%=(10)/(100)=0.10`

→ Probability of the spinner is P(R)+P(B)+P(G)=1

To find the probability of section green colored, substitute the value

`P(R)+P(B)+P(G)=1`

`0.25+0.10+P(G)=1`

`0.35+P(G)=1`

`P(G)=1-0.35`

`P(G)=0.65`

Convert into percentage,

`0.65=(65)/(100)* 100=65\%`

Therefore,The probability of the arrow landing on a section colored green is 65%.