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30 votes
-(y + 5) = 2(3y + 1)

User Per Salbark
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1 Answer

16 votes
16 votes

You have the following equation

-(y + 5) = 2(3y + 1)

First of all, you eliminate parenthesis, by taking into account that a parenthesis preceded by a minus sign, demand that all sign changes into the parenthesis when you open the parenthesis, just as follow:

-y - 5 = 2(3y) + 2(1) (Furthermore, you have applied distribution property)

-y - 5 = 6y + 2 (you made the products)

Next, you rest 6y and sum 5 in bot sides of the equation and you simplify:

-y -6y -5+5 = 6y -6y +2 +5

-7y + 0 = 0 + 7

-7y = 7

Finally, you divide both sides of the equation by -7:

-7y/(-7) = 7/(-7)

y = -1

Then, the solution to the equation is y=-1

User AdmiralJonB
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