Question

Hello, I am college algebra and I need help with finding the vertex of the graph of y=x²+3

Answer 1

We have the next equation

`y=x^2+3`

First we will calculate the x- coordinate of the vertex with the next formula

`x=-(b)/(2a)`

in this case a=1 (constant of the quadratic term) b=0 (constant of the linear term )

`x=-(0)/(2(1))=0`

then we substitute the value of x in the equation given in order to find the value of the y-coordinate of the vertex

`y=0^2+3=3`

the vertex is (0,3)

as we can see in the graph of the equation