Question

(Plz answer this)

23 grams of sodium reacted with 35.5g of chlorine. Calculate the mass of the sodium chloride compound formed.

Thank you!!! :)

Answer 1

Molar Masses:

MM of Na+ = 23 g / mol
MM of Cl- = 35.5 g / mol

Initially we must calculate the number of moles of each participant of the reaction, ie, sodium Na + and chlorine Cl-:

→ Number of moles of Na +


`n = (m)/(MM)`

`n = (23)/(23)`
n = 1 mol

→ Number of mols of Cl-


`n = (m)/(MM)`

`n = (35.5)/(35.5)`
n = 1 mol

Reaction:

Na + + Cl- -----------> NaCl

1 mole Na + ------------------ 1 mole NaCl
1 mole of Na + -------------- y

y = 1 mol of NaCl are produced

NaCl Molar Mass = 23 + 35.5 = 58.5 g / mol

1 mole of NaCl ---------------- 58.5 g
1 mol ----------------------- m

m = 58.5 grams of NaCl