Question

A rigid steel container with a volume of 100.0 liters is filled with nitrogen gas to a pressure of 30 atmospheres at 295 kelvins. how many moles of nitrogen gas does the cylinder contain

Answer 1

Data:

P (pressure) = 30 atm
V (volume) = 100.0 L
T (temperature) = 295 K
n (number of mols) = ?
R (Gas constant) = 0.082 (atm*L/mol*K)

Formula:


`p*V = n*R*T`

Solving:

`p*V = n*R*T`

`30*100.0 = n*0.082*295`

`3000 = 24.19n`

`24.19n = 3000`

`n = (3000)/(24.19)`

`\boxed{\boxed{n \approx 124.01\:mols}}\end{array}}\qquad\quad\checkmark`