Question

If we had 8.02 x 10²⁴ atoms of neon, how many moles would this be?

Answer 1

Number of moles = 13.3 moles

The appropriate ratio will be 1/6.02*10²³

Explanations:

According to the Avogadro's constant;

`\text{1mole}=6.02*10^(23)atoms`

Given the following parameters

Atoms of neon = 8.02 x 10²⁴ atoms

Find the moles of neon

`\begin{gathered} moles\text{ of neon}=(8.02*10^(24))/(6.02*10^(23)) \\ moles\text{ of neon=1.33}*(10^(24))/(10^(23)) \\ moles\text{ of neon}=1.33*10^1 \\ moles\text{ of neon}=13.3moles \end{gathered}`

Hence the number of moles this would be is approximately 13.3 moles

The appropriate ratio will be expressed as:

`8.02*10^(24)*(1)/(6.02*10^(23))`