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What is the ph of household ammonia in which the [h3o ] is 1.0x10-12 m?

1 Answer

7 votes
Data:

pH = ?

[ H_(3) O] = 1.0*10^(-12)
The logarithm of number 1 on any basis will always be equal to 0, therefore: Log10 (1) = 0

Solving:

pH = - log[ H_(3) O^+]

pH = -log1.0*10^(-12)

pH = 12 - log1.0

pH = 12 - 0

\boxed{\boxed{pH = 12}}\end{array}}\qquad\quad\checkmark

Note: For pH greater than 7 indicates that the substance is basic (pH > 7)
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