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Find the perimeter of the figure to the nearest hundredth.

Find the perimeter of the figure to the nearest hundredth.-example-1
User Isac
by
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1 Answer

11 votes

Answer:

Perimeter of figure is 31.85 inches

Explanation:

We have a rectangle and semi-circle in the figure.

First we will find perimeter of rectangle and semicircle and add them to find perimeter of rectangle.

First find perimeter of rectangle

The formula used is:
Perimeter\: of\: rectangle=2(length+width)

We have width = 7 in

length = 5 in

The perimeter is:


Perimeter\: of\: rectangle=2(length+width)\\Perimeter\: of\: rectangle=2(5+7)\\Perimeter\: of\: rectangle=2(12)\\Perimeter\: of\: rectangle=24\:in

The perimeter of rectangle = 24 in

Now, finding perimeter of semi-circle

The formula used is:
Perimeter\: of\: semi-circle=(\pi d)/(2)

Wee have diameter d = 5 in

So, perimeter is:


Perimeter\: of\: semi-circle=(\pi d)/(2)\\Perimeter\: of\: semi-circle=(3.14* 5)/(2)\\Perimeter\: of\: semi-circle=7.85\:in

So, Perimeter of semi-circle= 7.85 in

Now, finding Perimeter of figure

Perimeter of figure = Perimeter of Rectangle + Perimeter of semi-circle

Perimeter of figure = 24 + 7.85

Perimeter of figure = 31.85 inches

So, Perimeter of figure is 31.85 inches

User Rick Jolly
by
7.9k points

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