Question

What is an equation in point-slope form for the line that contains the points (-1, 4) and (11, -6)?

Answer 1

The equation in point-slope form is
`y-4=-(5)/(6)(x+1)`

Explanation:

Given points are;

(-1, 4) and (11, -6)

We will find the slope of the line through the given points.

Slope = m =
`(y_2-y_1)/(x_2-x_1)`

m =
`(-6-4)/(11-(-1))`

m =
`(-10)/(12)`

m =
`(-5)/(6)`

Point slope form of a line is given by;

`y-y_1=m(x-x_1)`

Putting the point (-1,4) and slope in the equation

`y-4=-(5)/(6)(x-(-1))\\y-4 =-(5)/(6)(x+1)`

Hence,

The equation in point-slope form is
`y-4=-(5)/(6)(x+1)`