Using the uniform distribution, it is found that there is a 0.625 = 62.5% probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.
An uniform distribution has two bounds, a and b.
The probability of finding a value above x is:
In this problem, uniformly distributed between 0 and 6 minutes, thus .
The probability of a time greater than 2.25 minutes is P(X > 2.25), thus:
0.625 = 62.5% probability that a randomly selected passenger has a waiting time greater than 2.25 minutes.