Question

Using 0.082 as your R value, what is the volume in L of 15 mols of a gas at 310K at 0.35 atm of pressure?

Answer 1

The volume of the gas is 1089.43 L

Step-by-step explanation

Given parameters:

Molar gas constant, R = 0.082 L⋅atm⋅K⁻¹⋅mol⁻¹

Moles, n = 15 mol

temperature, T = 310 K

Pressure, P = 0.35 atm

What to find:

The volume of the gas in L.

You can calculate for the volume of the gas using the ideal gas equation.

The ideal gas equation is PV= nRT

Substitute the values of R, n, T and P into the ideal gas equation:

`\begin{gathered} PV=nRT \\ 0.35\text{ atm }* V=15\text{ mol }*0.082\text{ }LatmK^(-1)mol^(-1)\text{ }*310\text{ K} \\ \text{Divide both sides by 0.35 atm} \\ \frac{0.35\text{ atm }* V}{0.35\text{ atm}}=\frac{15\text{ mol }*0.082\text{ }LatmK^(-1)mol^(-1)\text{ }*310\text{ K}}{0.35\text{ atm }} \\ V=1089.43\text{ }L \end{gathered}`