Answer:
10x+41=[5+-7]+[2x-2]
we move all terms to left 10x+41-[[5x-7+[2x-2]]=0
Explanation:
l calculate terms in parentheses
5x+2x-7-2
we add all the numbers together, and 7x-9 back to the equation -7x-9]
we get ride of parentheses 10x-7+9+41=0 we add all the numbers together,and all 3x+50=0
we move all the terms containg x to the left, all other therms to the right 3x=50
x=-50\3
x-50\3