Question

Which equation is the inverse of 5y+4 = (x+3)^2 + 1/2

A. Y=1/5 x^2 + 6/5 x + 11/10

B. Y=3 plus or minus square root 5x + 7/2

C. -5y -4 = -(x+3)^2 -1/2

D. Y= -3 plus or minus square root 5x + 7/2

Answer 1

d

Explanation:

credit to person above give them

Brainily

Answer 2

Option D is correct.

Explanation:

Given equation is
`5y+4=(x+3)^2+(1)/(2)`

We need to find inverse of the function.

Let x be the independent variable or the function is in x variable.

So,

we Simplify the given equation for variable of x.

`5y+4=(x+3)^2+(1)/(2)`

`5y+4-(1)/(2)=(x+3)^2`

`5y+(7)/(2)=(x+3)^2`

`\pm\sqrt{5y+(7)/(2)}=x+3`

`x+3=\pm\sqrt{5y+(7)/(2)}`

`x=-3\pm\sqrt{5y+(7)/(2)}`

Inverse of the given equation =
`-3\pm\sqrt{5y+(7)/(2)}`

Therefore, Option D is correct.