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PLZ HELP IF YOU CAN PLZ ANSWER ALL 1. Quan plans to spend less than $80 for buying groceries. He plans to spend $68.25 on food and spend the rest on juice. Each juice carton costs $3. He is curious how many juice cartons he can purchase before he runs out of money.

2. (a) Use x to represent the number of juice cartons Quan can purchase and write an inequality that can be used to solve for x.

2 Answers

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$80.00-$68.25=$11.75
x=?
j=$3
$11.75/$3.00=x
x=3.9 (0.9 is not one so you can have 3 cartons)
User Monte Jones
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Y=3X+68.25

80=3X+68.25
Subtract 68.25 from both sides
11.75=3X

Divide

11.75/3=3.91
He can't buy a portion of a juice but he doesn't have enough to buy 4

So he can afford 3 juice cartons
User Michael Hathi
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7.4k points