Question

greenbury has a population of 10,000 people and is icreasing at a rate of 1.2%.the population in 3 years will be

Answer 1

We know that the initial population is 10,000, since the popuation grows at a rate of 1.2% yearly the first year the population will be:

`\begin{gathered} 10,000+10,000(0.012)=10,000(1+0.012) \\ =10,000(1.012) \end{gathered}`

Remembering that the population growth is given as:

`y=ab^x`

where y is the final population, a is the initial population and b is the growth factor we have in this case that:

`y=10,000(1.012)^x`

Then, after three years we will have:

`\begin{gathered} y=10,000(1.012)^3 \\ =10364.34 \end{gathered}`

Therefore after three years we will have approximately 10364 people.