Question

How many grams of Li3N are produced when 4.7 X 10(23) atoms of lithium react?

Answer 1

`m_(Li_3N)=9.06gLi_3N`

Step-by-step explanation:

Hello!

In this case, since the reaction between nitrogen and lithium to obtain lithium nitride is:

`6Li+N_2\rightarrow 2Li_3N`

Starting by that amount of atoms of lithium, we first need to compute the moles of lithium via the Avogadro's number:

`n_(Li)=4.7x10^(23)atoms*(1molLi)/(6.022x10^(23)atoms)=0.78molLi`

Now, by using the 6:2 mole ratio between lithium and lithium nitride and the molar mass of this product (34.83 g/mol), we can compute the required grams as shown below:

`m_(Li_3N)=0.78molLi*(2molLi_3N)/(6molLi)*(34.83gLi_3N)/(1molLi_3N) \\\\m_(Li_3N)=9.06gLi_3N`

Best regards!