Question

. What pressure will be exerted by 0.7 mol of a gas at 23 C when contained in a vessel whose volume is 1.1 L?

Answer 1

15.46atm

Explanations:

According to the ideal gas equation;

`PV=nRT`

where:

• P is the ,pressure ,of the gas

,

• V is the volume of the gas = 1.1L

,

• n is the number of moles = 0.7mol

,

• R is the ,Gas constant, = 0.08206Latm/molK

,

• T is the temperature = 23 + 273 = 296K

Substitute the given parameters into the formula

`\begin{gathered} P=(nRT)/(V) \\ P=(0.7*0.08206*296)/(1.1) \\ P=(17.0028)/(1.1) \\ P=15.46atm \end{gathered}`

Hence the pressure of the gas that will be exerted is 15.46atm