Question

An elevator of mass 3000 kg is ascending at a steady speed of 2.0 m/s. What is the

force in the cable supporting the elevator?

Answer 1

F = mg
we know the mass and g = 9.8 m/s/s

Answer 2

`T = 29430 N`

Step-by-step explanation:

When the elevator is moving at uniform speed then we can say that acceleration of the elevator is zero

so we will have

`T - mg = ma`

here T = tension in the supporting cable

mg = weight of elevator

now if the elevator is moving with steady speed

then we will have

`T - mg = 0`

`T = mg`

`T = (3000)(9.81)`

`T = 29430 N`