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A student is instructed to make 0.250 liter of a 0.200 m aqueous solution of ca(no3)2. what is a correct numerical setup for calculating the total number of moles of ca(no3)2 needed to make 0.250 liter
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A student is instructed to make 0.250 liter of a 0.200 m aqueous solution of ca(no3)2. what is a correct numerical setup for calculating the total number of moles of ca(no3)2 needed to make 0.250 liter of the 0.200 m calcium nitrate solution?

User Cmdv
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1 Answer

7 votes

Answer:

0.250L x (0.200mol)/ (1L)

Step-by-step explanation:

User Nawnit Sen
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