Question

The function y= x2 - 10x+ 31 has a
value of

Answer 1

• y = 6 at x = 5

Explanation:

It is assumed the question is about finding the minimum value as the given function has no maximum value, it is + ∞ as the coefficient of x² is positive

The minimum/maximum value of a quadratic function is the vertex, which is at:

• x = -b/2a

For the given function y = x² -10x + 31, the vertex is:

• x = - (-10)/2*1 = 10/2 = 5

The value of y at this point is:

• y = 5² - 10*5 + 31 = 25 - 50 + 31 = 6

The point is

• (5, 6)