Question

Which equation is the inverse of y = 16x2 + 1?
D. y= +or- sqrt x-1/4 is the correct answer

Answer 1

I hope this helps you



y-1=16x^2



y-1/16=x^2



x= square root of y-1/4



y^-1= square root of x-1/4

Answer 2

we have

`y=16x^(2) +1`

Step 1

Exchange the variables x for y and y for x

`x=16y^(2) +1`

Step 2

Clear variable y

`x=16y^(2) +1`

Subtract
`1` both sides

`x-1=16y^(2) +1-1`

`x-1=16y^(2)`

Divide by
`16` both sides

`(x-1)/16=16y^(2)/16`

`(x-1)/16=y^(2)`

square root both sides

`y=(+/-)\sqrt{(x-1)/(16)} \\ \\y=(+/-) (1)/(4) √(x-1)`

Step 3

Find the inverse

Let

`f(x)^(-1) =y`

so

`f(x)^(-1)=(+/-) (1)/(4) √(x-1)`

therefore

the answer is

`f(x)^(-1)=(+/-) (1)/(4) √(x-1)`