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Helpppppp (tell me how to solve you dont need to awnser them all)

Helpppppp (tell me how to solve you dont need to awnser them all)-example-1
User Tamlyn
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Explanation:

A) having a blue first has a 1 out of 5 chance

then lets say you got the 1/5, after that getting an X

gives you a 1/3 probability, you can multiply then to find

x and a blue probability is 1/5 * 1/3 meaning you have

1/15 chance to get a blue x

O) there is 3/5 chance not to get red since there are 2 reds

then again you have a 1/3 chance of getting an x

giving you 3/5 * 1/3 meaning 1/5 chance to get

not red and x

for prove you can write all possibilities

blue x, blue y, blue y

white x, white y, white y

white x, white y, white y

red x, red y, red y

red x, red y, red y

meaning 15 possible outcomes in which

blue y, white x or red x have 2/15 probability

red y or white y have a 4/15

leaving blue x with a 1/15 probability

you can apply the same rule with the rest

however if the question is something like probability of orange z, or anything not mentioned its automatically 0/ all possible outcomes, or if its like not orange and not z, its 15/15 then, how ever if its not orange and y its all the Ys meaning 10/15

you just have to understand the question

like lemme try question 2 , W

probability of not white is 3/4 scince there is only 1 white and other aren't and getting an odd is 3/6 or 1/2, multiplying them you get 3/8

all outcomes

w = white

nw = not white

nw1 , nw2 , nw3 , nw4 , nw5 , nw6 6

nw1 , nw2 , nw3 , nw4 , nw5 , nw6 6

nw1 , nw2 , nw3 , nw4 , nw5 , nw6 6

w1 , w2 , w3 , w4 , w5 , w6 6 = 24

9/total outcomes = 9/24 or back to 3/8

User WhiteFluffy
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