1 Answer

Bunji · Answer 1 · 2023-12-14T03:26:16+0000

Given the function:

$y=\cot (x+(\pi)/(6))$

Let's graph the function.

Apply the form:

$y=a\cot (bx-c)+d$

Thus, we have the values:

a = 1

b = 1

c = - π/6

d = 0

Here, the graph does not have a minimum of maximum value, hence there is no amplitude.

To find the period, we have:

$period=(\pi)/(|b|)=(\pi)/(1)=\pi$

For the phase shift, we have:

$(c)/(b)=(-(\pi)/(6))/(1)=-(\pi)/(6)$

Therefore, the graph of the function is:

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