Question

What is the volume of 5.0 moles of O2 at STP?

Answer 1

The volume of 5.0 moles of O2 at STP is 112.0 liters, which is calculated by multiplying the molar volume at STP (22.4 liters per mole) by the number of moles.

Step-by-step explanation:

To calculate the volume of 5.0 moles of O2 at STP (standard temperature and pressure), we utilize the molar volume of a gas at STP which is 22.4 liters per mole. Since STP is defined as 0°C (273 K) and 1 atm of pressure, every mole of an ideal gas occupies this volume.

Here is a step-by-step explanation of the calculation:

We know that 1 mole of a gas at STP occupies 22.4 liters (from Figure 6.6.1) and Figure 6.6.5).

Since the student has 5.0 moles of O2, we multiply the number of moles by the molar volume: 5.0 moles × 22.4 liters/mole.

The resulting volume is therefore 5.0 × 22.4 = 112.0 liters.

So, the volume that 5.0 moles of O2 would occupy at STP is 112.0 liters.

Answer 2

At the STP, the molar volume is equal to 22.414 L of O2

As are five moles of oxygen gas:

22.414 * 5 = 112.07 L

Answer:
112.07 L of O2

or


`(x)/(5.00\:mol) = (22.414\:L)/(1.00\:mol)`

`x = 5.00*22.414`

`\boxed{x = 112.07\:L}`