A theater company with 8 actors is putting on a play that has 4 roles. in how many different ways can the director assign actors to those roles?

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asked Jan 28, 2018 223k views

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Mabergerx · Answer 1 · 2018-02-01T21:52:35+0000

Assuming no actor takes more than 1 role, we have 70 possible combinations.

Our problem is expressed as 8C4.

This is equal to 8!/[(8-4)!*4!]. This is equal to 70. Have a nice day!

A theater company with 8 actors is putting on a play that has 4 roles. in how many different ways can the director assign actors to those roles?

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