Question

I need help with this practice I am having a tough time solving it properly

Answer 1

Given:

There are given that the parent functions as a cosine function:

Where,

The amplitude of the function is 9.

The vertical shift is 11 units down.

Step-by-step explanation:

To find the cosine function, we need to see the standard form of the cosine function:

`f(x)=acos(bx+c)+d`

Where,

a is the amplitude of the function,

Now,

According to the question:

The amplitude of the function is 9, which means:

`f(x)=9cos(bx+c)+d`

The vertical shift is 11 units down, which means:

`f(x)=9cos(bx+c)-11`

For period:

`\begin{gathered} f(x)=-9cos((12\pi)/(7)x+0)-11 \\ f(x)=-9cos((12\pi)/(7)x)-11 \end{gathered}`

Final answer:

Hence, the cosine function is shown below;

`f(x)=-9cos((12\pi)/(7)x)-11`