Question

Which of the following equations represents the graph of a line that is parallel to the graph of y = -ax + b and goes through the point (-1, 2)?Group of answer choicesy + 2 = -a(x - 1)y - 2 = -a(x + 1)y - 2 = (1/a)(x + 1)y + 2 = (1/a)(x - 1)

Answer 1

To find the equation of the line, parallel to the line y=-ax+b, that passes through the point (-1,2), you have to keep in mind that the slope of two parallel lines is equal.

The slope of the known line is the coefficient of the x-term. in this case, the slope is equal to "-a"

Once you have determined the slope of the line, you can use the point-slope form to find the equation of the line:

`y-y_1=m(x-x_1)`

Where

m is the slope of the line

(x₁,y₁) are the coordinates of one point of the line:

The coordinates of the point of the line are x₁= -1 and y₁= 2 and the slope is m=-a, so that:

`\begin{gathered} y-2=-a(x-(-1)) \\ y-2=-a(x+1) \end{gathered}`

So, the equation of the line, parallel to y=-ax+b, passes through the point (-1,2) is y-2=-a(x+1)