Question

36. What is the equation of the line that passes through the points (4, 5) and (5,6)?A. y = x + 1B. y = –x + 2C. y = –3x – 2D. y = –5x + 10

Answer 1

STEP - BY - STEP EXPLANATION

What to find?

Equation of a straight line.

Given:

Points; (4, 5) and (5,6)

Step 1

Identify its coordinate.

x₁= 4 y₁=5

x₂=5 y₂=6

Step 2

Determine the slope (m) using the formula below:

`\begin{gathered} slope(m)=(y_2-y_1)/(x_2-x_1) \\ \\ =(6-5)/(5-4) \\ \\ =1 \end{gathered}`

Step 3

Find the intercept(c) using the formula below:

`\begin{gathered} y=mx+c \\ \\ 5=(1)(4)+c \\ \\ c=5-4 \\ =1 \end{gathered}`

Step 4

Form the equation by substituting m=1 and c=1 into the general equation.

`y=x+1`

ANSWER

A. y=x+1