What is the general equation of a sine function with an amplitude of 2, a period of pi and a horizontal shift of pi units?

Question

asked Jul 3, 2018 59.5k views

2 Answers

Kiko Fernandez · Answer 1 · 2018-07-09T06:32:13+0000

Answer:

$y=2sin(2(x-\pi))$

Explanation:

The general equation of a sine function can be written as:

$y=(Amplitude)sin({(2\pi)/(period))(x-shift)$

Now, we are given that the amplitude is
and period is of
$\pi$ with a horizontal shift of
$\pi$ units, thus the general equation becomes

$y=2sin((2\pi)/(\pi))(x-\pi)$

$y=2sin(2(x-\pi))$

which is the required general equation of a sine function.