Question

1. Consider this system of linear equations:=-S y = x - 3y = -x +141a. Without graphing, determine how many solutions you would expectthis system of equations to have. Explain your reasoning.Your answer1b. Try solving the system of equations algebraically and describe theresult that you get. Does it match your prediction? *

Answer 1

we have the system of equations

y=(4/5)x-3 -------> equation A

y=(4/5)x+1 -----> equation B

In this problem

we have two parallel lines with different y-intercept

because the slopes are equal

that means

The system has no solution

Part b

Solving the system by substitution

equate equation A and equation B

(4/5)x-3=(4/5)x+1

simplify

-3=1 -----> is not true

that means

the system has no solution